Let centre of circle is C and circle cuts the y -axis at B and A. Let mid-point of chord BA is M.
CB=√MC2+MB2 √32+42=5= radius of circle ∴ equation of circle is (x−3)2+(y−5)2=52 (3,10) satisfies this equation. Although there will be another circle satisfying the same conditions that will lie below the x -axis having equation (x−3)2+(y−5)2=52