=1 at any point P(6cosθ,4sinθ) is 3secθx−2cosecθy=10 this normal is also the normal of the circle passing through the point (2,0) So, 6secθ=10 or sinθ=0 (Not possible) cosθ=
3
5
and sinθ=
4
5
so point P=(
18
5
,
16
5
) So the largest radius of circle √320 So the equation of circle (x−2)2+y2=