Solution:
Let R={(3,3),(5,5),(9,9),(12,12), (5,12),(3,9),(3,12), (3,5)\} be a relation on set
A={3,5,9,12}
Clearly, every element of A is related to itself.
Therefore, it is a reflexive.
Now, R is not symmetry because 3 is related to 5 but 5 is not related to 3.
Also R is transitive relation because it satisfies the property that if aRb and bRc then aRc.
© examsnet.com