Given, two sides of parallelogram are
r4x+5y=07x+2y=0 and 7x+2y=0
Both lines are passing through origin.
Thus, point
A=(0,0)The equation of diagonal is
11x+7y=9Point
D is the point of intersection of
4x+5y=0and
11x+7y=9So, coordinate of
D=(,−)Also, point
B is the point of intersection of
7x+2y=0 and
11x+7y=9So, coordinate of point
B=(−,)We know that, diagonals of parallelogram bisects each other. Let
P is the middle point of
BD.
So, coordinate of
P=(,)=(,)Now, equation of diagonal
ACy−0=(x−0)⇒y=x⇒y=x∴ Diagonal AC passes through
(2,2).