Given Height of satellite from planet's surface, h=11R So, the total distance from the centre of planet =11R+R=12R Time period of planet =24h Similarly, the total distance of second satellite from the centre of planet =2R+R=3R Using the Kepler's law T2∝R3 ⇒(
T1
T2
)=(
R1
R2
)3∕2 Substituting the values in the above equation, we get (
24
T
)=(
12R
3R
)3∕2 ∴ The time period of another satellite is 3h.