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JEE Main Physics Class 11 Gravitation Part 2 Questions
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© examsnet.com
Question : 43
Total: 89
Two identical particles each of mass '
m
' go round a circle of radius a under the action of their mutual gravitational attraction. The angular speed of each particle will be :
[15-Apr-2023 shift 1]
√
Gm
a
3
√
Gm
4
a
3
√
G
m
2
a
3
√
Gm
8
a
3
Validate
Solution:
F
C
=
m
ω
2
a
G
m
2
(
2
a
)
2
=
m
ω
2
a
ω
=
√
G
m
4
a
3
© examsnet.com
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