Given, mass of block, m=√3kg Coefficient of friction, µ=1∕3√3 According to diagram,
Let F be the force applied on the body, w be the weight (=mg), N be the normal reaction. Friction force f=µN For no movement of body along X-axis, net force along X-axis should be zero. If, Fy be the net force along y-axis then it will also be zero because body is not accelerating at all. ∴N=Fsin60∘+mg ⇒N=
√3
2
F+10√3 . . . (i) ∴N=Fsin60∘ ⇒N=
√3
2
F+1 Similarly, Fx=Fcos60∘−µN=0 From Eq. (i), we get ⇒