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JEE Main Physics Class 11 Oscillations Part 1 Questions
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© examsnet.com
Question : 2
Total: 100
Two simple harmonic motion, are represented by the equations
y
1
=
10
sin
(
3
π
t
+
π
3
)
and
y
2
=
5
(
sin
3
π
t
+
√
3
cos
3
π
t
)
Ratio of amplitude of
y
1
to
y
2
=
x
:
1
. The value of x is ............ .
[27 Aug 2021 Shift 2]
Your Answer:
Validate
Solution:
Given,
y
1
=
10
sin
(
3
π
t
+
π
3
)
A
1
=
10
y
2
=
5
(
sin
3
π
t
+
√
3
cos
3
π
t
)
=
5
sin
3
π
t
+
5
√
3
cos
3
π
t
Amplitude of
S
H
M
2
is
A
2
=
√
5
2
+
(
5
√
3
)
2
=
√
25
+
75
=
√
100
=
10
∴
Ratio of amplitudes,
A
1
A
2
=
10
10
=
1
:
1
x
=
1
© examsnet.com
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