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JEE Main Physics Class 11 Oscillations Part 1 Questions
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© examsnet.com
Question : 23
Total: 100
A pendulum is executing simple harmonic motion and its maximum kinetic energy is
K
1
.
If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is
K
2
.
[11 Jan 2019, II]
K
2
=
2
K
1
K
2
=
K
1
2
K
2
=
K
1
4
K
2
=
K
1
Validate
Solution:
K
=
1
2
m
ω
2
x
2
⇒
K
max
=
1
2
m
ω
2
A
2
A
=
L
θ
ω
=
√
g
L
⇒
K
=
1
2
m
.
g
L
.
L
2
θ
2
=
1
2
m
g
L
θ
2
∴
K
1
K
2
=
L
2
L
=
1
2
⇒
K
2
=
2
K
1
∴
K
1
K
2
=
L
2
L
=
1
2
⇒
K
2
=
2
K
1
© examsnet.com
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