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JEE Main Physics Class 11 Oscillations Part 1 Questions
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© examsnet.com
Question : 81
Total: 100
A coin is placed on a horizontal platform which undergoes vertical simple harmonic motion of angular frequency
ω
. The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time
[2006]
at the mean position of the platform
for an amplitude of
g
m
2
for an amplitude of
g
2
m
2
at the highest position of the platform
Validate
Solution:
For block
A
to move in
S
H
M
.
m
g
−
N
=
m
ω
2
x
where
x
is the distance from mean position For block to leave contact
N
=
0
⇒
m
g
=
m
ω
2
x
⇒
x
=
g
ω
2
© examsnet.com
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