Given, the Young’s modulus of the steel rod, Y = 2 ×
1011 Pa
Thermal coefficient of the steel rod, α =
10−5ºC
The length of the steel rod, I = 4 m
The area of the cross-section, A = 10
cm2 The temperature difference, ΔT = 400°C
As we know that,
Thermal strain = α ΔT
Using the Hooke’s law
Young's modulus
(Y)=| Thermalstress |
| Thermalstrain |
= Thermal stress, F = YA α Δ T
Substitute the values in the above equation, we get
F=2×1011×10×10−4×10−5×(400) =8×105N Comparing with,
F=x×105N The value of the x = 8.