M. I of a circular wire about an axis nn ' passing through the centre of the circle and perpendicular to the plane of the circle =MR2
As shown in the figure, X -axis and Y -axis lie along diameter of the ring. Using perpendicular axis theorem IX+IY=IZ Here, IX and IY are the moment of inertia about the diameter. ⇒2IXA=MR2[∵IX=IY( by symmetry ) and IZ=MR2] ∴IX=