Given, equation of alternating current, i=[√42sin(
2π
T
t)+10]A From given equation, we get i=i1+i2 where, i1=√42sin(
2π
T
t)A and i2=10A Now, i1 is oscillating current, whereas i2 is direct current and its value does not change with time. (i1)rms=
√42
√2
=√21A (i2)rms=10A We know that, irms2=(i1)rms2+(i2)rms2 Substituting the values, we get irms=√(√21)2+102=√121 ⇒irms=11A Thus, RMS value of given equation of current is 11 A.