Given, frequency,
f=500MHz=5×108Hz B=8.0×10−8T ∴ Magnitude of peak value of magnetic field is given by
B0=8×10−8T We know that,
=C where,
E0 is the magnitude of peak value of electric field and
c is the speed of electromagnetic wave in air (or vacuum).
⇒E0=cB0 =3×108×8×10−8=24V∕m Since, the direction of propagation of electromagnetic wave is perpendicular to the direction of
E and
B both.
∴ Direction of propagation is given by
×.
As, the wave is travelling in
y-direction,
and the magnetic field is in z-direction.
⇒×= =− ∴ The value of electric field will be
−24V∕m.