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JEE Main Physics Class 12 Electronic Devices Part 2 Questions
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© examsnet.com
Question : 76
Total: 111
A Zener diode of power rating
2
W
is to be used as a voltage regulator. If the Zener diode has a breakdown of
10
V
and it has to regulate voltage fluctuated between
6
V
and
14
V
, the value of
R
S
for safe operation should be........ Ω
[27 Aug 2021 Shift 2]
Your Answer:
Validate
Solution:
Given, power,
P
=
2
W
Zener breakdown voltage,
V
z
=
10
V
Voltage range,
(
V
1
to
V
2
)
=
6
V
and
14
V
Let resistance be
R
.
Since,
P
=
V
I
z
Zener current,
I
z
=
P
V
z
=
2
10
=
0.2
A
For safe operation of Zener diode,
I
z
=
I
s
=
0.2
A
∴
V
2
−
V
z
=
I
s
R
s
⇒
14
−
10
=
I
s
R
s
⇒
R
s
=
4
0.2
=
40
2
=
20
Ω
© examsnet.com
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