The distance of point A(√2,√2) from the origin, rA=√(√2)2+(√2)2=√4=2 units. The distance of point B(2,0) from the origin, rB=√(2)2+(0)2=2 units Now, potential at A, due to charge θ=10−3µC VA=
1
4π∈0
.
Q
(rA)
Potential at B, due to charge Q=10−3QCVB=
1
4π∈0
.
Q
(rB)
∴ Potential difference between the points A and B is given by VA−VB=