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JEE Main Physics Class 12 Electrostatic Potential and Capacitance Part 2 Questions
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Question : 66
Total: 100
Two metallic plates form a parallel plate capacitor. The distance between the plates is '
d
'. A metal sheet of thickness
d
2
and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor?
[25-Jun-2022-Shift-2]
2
:
1
1
:
2
1
:
4
4
:
1
Validate
Solution:
C
e
q
=
ε
0
A
d
−
d
2
+
d
2
k
=
ε
0
A
d
2
=
2
ε
0
A
d
If
C
=
ε
0
A
d
⇒
C
e
q
=
2
C
or
C
new
C
old
=
2
1
© examsnet.com
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