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Test Index
JEE Main Physics Class 12 Ray Optics and Optical Instruments Part 2 Questions
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© examsnet.com
Question : 95
Total: 112
A ray of light passes from a denser medium to a rarer medium at an angle of incidence i. The reflected and refracted rays make an angle of 90° with each other. The angle of reflection and refraction are respectively r and r'. The critical angle is given by :
[22 Jul 2021 Shift 2]
sin
−
1
(cotr)
tan
−
1
(
sin
i
)
sin
−
1
(
tanr'
)
sin
−
1
(
tanr
)
Validate
Solution:
r
+
r
′
+
90
°
=
180
°
⇒
r
′
=
90
−
r
=
90
−
i
n
1
sin
i
=
n
2
sin
r
′
=
n
2
sin
(
90
−
i
)
n
1
sin
i
=
n
2
cos
i
⇒
tan
i
=
n
2
n
1
Now
sin
C
=
n
2
n
1
=
tan
i
⇒
C
=
sin
−
1
(
tan
i
)
=
sin
−
1
(
tan
r
)
© examsnet.com
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