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JEE Mains 11-Apr-2023 Shift 1 Solved Paper
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© examsnet.com
Question : 21
Total: 90
The number of integral terms in the expansion of
(
3
1
2
+
5
1
4
)
680
is equal to :
[11-Apr-2023 shift 1]
Your Answer:
Validate
Solution:
The number of integral term in the expression of
(
3
1
2
+
5
1
4
)
680
is equal to
General term
=
680
C
r
(
3
1
2
)
680
−
r
(
5
1
4
)
r
=
680
C
r
3
680
−
r
2
5
r
4
Values' s of
r
, where
r
4
goes to integer
r
=
0
,
4
,
8
,
12
,
.
.
.
.
.
.
680
All value of
r
are accepted for
680
−
r
2
as well so
No of integral terms
=
171
.
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