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JEE Mains 11-Apr-2023 Shift 1 Solved Paper
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© examsnet.com
Question : 25
Total: 90
Let
S
=
S
=
109
+
108
5
+
107
5
2
+
.
.
.
.
+
2
5
107
+
1
5
108
. Then the value of
(
16
S
−
(
25
)
−
54
)
is equal to _______.
[11-Apr-2023 shift 1]
Your Answer:
Validate
Solution:
S
=
109
+
108
5
+
107
5
2
.
.
.
.
.
.
+
1
5
108
S
5
=
109
5
+
108
5
2
.
.
.
.
.
.
⋅
2
5
108
+
1
5
109
4
S
5
=
109
−
1
5
−
1
5
2
.
.
.
.
.
.
−
1
5
108
−
1
5
109
=
109
−
(
1
5
(
1
−
1
5
109
)
)
(
1
−
1
5
)
)
=
109
−
1
4
(
1
−
1
5
109
)
=
109
−
1
4
+
1
4
×
1
5
109
S
=
5
4
(
109
−
1
4
+
1
4.5
109
)
16
S
=
20
×
109
−
5
+
1
5
108
16
S
−
(
25
)
−
54
=
2180
−
5
=
2175
© examsnet.com
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