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JEE Mains 11-Apr-2023 Shift 1 Solved Paper
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© examsnet.com
Question : 48
Total: 90
The current sensitivity of moving coil galvanometer is increased by
25
%
.This increase is achieved only by changing in the number of turns of coils and area of cross section of the wire while keeping the resistance of galvanometer coil constant. The percentage change in the voltage sensitivity will be :
[11-Apr-2023 shift 1]
+
25
%
−
25
%
−
50
%
Zero
Validate
Solution:
τ
=
mB
A
=
area of coil
K
θ
=
IANB
B
=
magnetic field
θ
I
=
ANB
K
Currect senstivity
1.25
(
θ
I
)
2
=
(
θ
I
)
1
.
.
.
.
.
.
.
.
.
.
(
1
)
1.25
[
AN
2
B
K
]
=
[
AN
1
B
K
]
1.25
=
N
1
N
2
=
5
4
.
.
.
.
.
.
(
2
)
⇒
R
=
δ
ℓ
a
=
const.
⇒
ℓ
=
a
Voltage sensitivity
=
θ
V
=
θ
ℝ
=
Current sensitivity
R
R
=
constant
Voltage sensitivity
∝
current sensitivity
© examsnet.com
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