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JEE Mains 11-Apr-2023 Shift 2 Solved Paper
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© examsnet.com
Question : 6
Total: 90
Let the mean of 6 observations
1
,
2
,
4
,
5
,
x
and
y
be
5
and their variance be 10 . Then their mean deviation about the mean is equal to
[11-Apr-2023 shift 2]
7
3
10
3
8
3
3
Validate
Solution:
Mean of
1
,
2
,
4
,
5
,
x
,
y
is 5
and variance is 10
⇒
mean
⇒
12
+
x
+
y
6
=
5
12
+
x
+
y
=
30
x
+
y
=
18
and by variance
x
2
+
y
2
+
46
6
−
5
2
=
10
x
2
+
y
2
=
164
x
=
8
y
=
10
mean daviation
=
|
x
−
x
|
6
⇒
4
+
3
+
1
+
0
+
3
+
5
6
=
16
6
=
8
3
© examsnet.com
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