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JEE Mains 12-Apr-2023 Shift 1 Solved Paper
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© examsnet.com
Question : 31
Total: 90
The ratio of escape velocity of a planet to the escape velocity of earth will be :-
Given : Mass of the planet is 16 times mass of earth and radius of the planet is 4 times the radius of earth.
[12-Apr-2023 shift 1]
1
:
4
4
:
1
2
:
1
1
:
√
2
Validate
Solution:
Given mass of planet
=
16
mass of the earth
(
m
p
=
16
m
e
)
r
p
=
4
r
o
We know
V
escape
=
√
2
G
m
R
,
V
esplanet
V
esearth
=
?
V
es plavet
V
es earth
=
√
2
GM
p
R
p
×
R
e
2
GM
e
=
√
M
p
M
e
×
R
e
R
p
=
√
16
m
e
m
e
×
R
e
4
R
e
=
√
16
4
=
2
:
1
V
esplanet
V
eseath
=
2
1
© examsnet.com
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