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JEE Mains 13-Apr-2023 Shift 1 Solved Paper
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© examsnet.com
Question : 19
Total: 90
Let
y
=
y
1
(
x
)
and
y
=
y
2
(
x
)
be the solution curves of the differential equation
d
y
d
x
=
y
+
7
with initial conditions
y
1
(
0
)
=
0
and
y
2
(
0
)
=
1
respectively. Then the curves
y
=
y
1
(
x
)
and
y
=
y
2
(
x
)
intersect at
[13-Apr-2023 shift 1]
no point
infinite number of points
one point
two points
Validate
Solution:
d
y
d
x
=
y
+
7
⇒
d
y
d
x
−
y
=
7
I.F.
=
e
−
x
y
e
−
x
=
∫
7
e
−
x
dx
⇒
y
e
−
x
=
−
7
e
−
x
+
c
⇒
y
=
−
7
+
c
e
x
−
7
+
7
e
x
=
−
7
+
8
e
x
⇒
e
x
=
0
No solution
© examsnet.com
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