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JEE Mains 13-Apr-2023 Shift 1 Solved Paper
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© examsnet.com
Question : 51
Total: 90
When a resistance of
5
Ω
is shunted with a moving coil galvanometer, it shows a full scale deflection for a current of
250
mA
, however when
1050
Ω
resistance is connected with it in series, it gives full scale deflection for 25 volt. The resistance of galvanometer is ________
Ω
.
[13-Apr-2023 shift 1]
Your Answer:
Validate
Solution:
I
g
(
G
)
=
(
250
−
I
g
)
5
I
g
=
1250
5
+
G
m
A
For voltmeter,
V
=
I
g
R
25
=
I
g
(
G
+
1050
)
From equation (1),
25
=
1250
×
10
−
3
G
+
5
(
G
+
1050
)
20
(
G
+
5
)
=
G
+
1050
19
G
=
1050
−
100
G
=
950
19
=
50
Ω
© examsnet.com
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