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JEE Mains 13-Apr-2023 Shift 1 Solved Paper
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© examsnet.com
Question : 83
Total: 90
20
mL
of calcium hydroxide was consumed when it was reacted with
10
mL
of unknown solution of
H
2
SO
4
. Also
20
mL
standard solution of
0.5
MHCl
containing 2 drops of phenolphthalein was titrated with calcium hydroxide, the mixture showed pink colour when burette displayed the value of
35.5
mL
whereas the burette showed
25.5
mL
initially. The concentration of
H
2
SO
4
is _______ M.(Nearest integer)
[13-Apr-2023 shift 1]
Your Answer:
Validate
Solution:
miliequivalent of
Ca
(
OH
)
2
=
miliequivalent of
H
2
SO
4
M
1
×
2
×
20
=
M
2
×
2
×
10
2
M
1
=
M
2
miliequivalent of
HCl
=
miliequivalent of
Ca
(
OH
)
2
20
×
0.5
=
10
×
M
1
×
2
M
1
=
0.5
M
Concentration of
H
2
SO
4
=
M
2
=
2
M
1
=
2
×
0.5
=
1
M
© examsnet.com
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