(p∧∼q)∨(∼p∧q)(∼p∧∼q) (α,β) (∼p)∨(∼q) Plane passing through (0,−1,2) and (−1,2,1) then vector in plane <−1,3,−1> vector parallel to plane is ⟨4,2,−6⟩ normal vector to plane L2 (
→
n
)=|
^
i
^
j
^
k
−1
3
−1
4
2
−6
| =i(−16)−
^
j
(10)+
^
k
(−14)
→
n
=<8,5,7> Equation of plane 8(x−0)+5(y+1)+7(z−2)=0 ⇒8x+5y+7z=9 From given options point (−2,5,0) lies on plane.