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KEAM 2011 Math Paper
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© examsnet.com
Question : 7
Total: 120
The equation of the perpendicular bisector of the line segment joining A(-2, 3) and B(6, -5) is
x
−
y
=
−
1
x
−
y
=
3
x
+
y
=
3
x
+
y
=
1
x
+
y
=
−
1
Validate
Solution:
The equation of the line passing through the points (-2,3) and (6,-5) is
(
y
−
3
)
=
−
5
−
3
6
+
2
(
x
+
2
)
⇒
(
y
−
3
)
=
−
1
(
x
+
2
)
⇒
y
−
3
=
−
x
−
2
⇒
y
=
−
x
+
1
...(i)
Now, the slope of perpendicular bisector of this line is
=
−
1
(
−
1
)
=
1
and the perpendicular bisector passing through the mid point of this line is (2,-1)
Then, equation of perpendicular bisector is
(
y
+
1
)
=
1
(
x
−
2
)
⇒
y
+
1
=
x
−
2
⇒
x
−
y
=
3
© examsnet.com
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