Let the required point be P(x1,y1). The equation of the given curve is y=3x2−11x−15 ⇒
dy
dx
=6x−11 ⇒(
dy
dx
)(x1,y1)=6x1−11 since, the tangent at P is parallel to the line joining (5,5) and (11,227) . ∴ Slope of the tangent at P= Slope of the line joining (5,5) and (11,227) ⇒(