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KEAM 2019 Math Paper
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© examsnet.com
Question : 49
Total: 121
(
7
−
4
√
3
)
x
2
−
4
x
+
3
+
(
7
+
4
√
3
)
x
2
−
4
x
+
3
=
14
then
x
=
?
3
,
3
±
√
3
3
±
√
2
,
3
2
±
√
3
,
2
2,1
2
,
2
±
√
2
Validate
Solution:
As,
(
7
+
4
√
3
)
(
7
−
4
√
3
)
=
1
Hence, the equation becomes
y
+
1
y
=
14
y
=
(
7
−
4
√
3
)
x
2
−
4
x
+
3
⇒
y
2
−
14
y
+
1
=
0
⇒
y
=
7
±
4
√
3
So,
y
=
7
+
4
√
3
⇒
x
2
−
4
x
+
3
=
−
1
⇒
x
=
2
,
2
and
y
=
7
−
4
√
3
⇒
x
2
−
4
x
+
3
=
1
⇒
x
=
2
±
√
2
© examsnet.com
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