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KEAM 2019 Math Paper
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© examsnet.com
Question : 50
Total: 121
If
z
is a normal root of
√
[
7
]
−
1
then
z
85
+
z
142
+
z
191
is
x
0
z
−
1
2
None of these
Validate
Solution:
Given,
z
7
=
−
1
Hence,
z
85
+
z
142
+
z
191
=
(
z
7
)
z
2
+
(
z
7
)
20
⋅
z
2
+
(
z
7
)
27
⋅
z
2
=
(
−
1
)
z
2
+
(
−
1
)
20
⋅
z
2
+
(
−
1
)
27
⋅
z
2
=
z
+
z
2
−
z
2
=
z
© examsnet.com
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