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KEAM 2019 Physics and Chemistry Paper
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© examsnet.com
Question : 28
Total: 120
The electric field of an electromagnetic wave in free space is given by
→
E
=
5
sin
(
2
π
3
z
−
ω
t
)
∧
y
V
∕
m
.
Which of the following statements is correct?
The wave propagates along
^
y
The wave vector is given
→
k
=
2
π
3
∧
z
The wavelength of the electromagnetic wave is
1
3
m
The corresponding magnetic field is
→
B
=
5
c
cos
(
2
π
3
z
−
ω
t
)
∧
x
T
The frequency of the wave is approximately
10
6
H
z
Validate
Solution:
Given, the electric part of electromagnetic wave
E
=
5
sin
(
2
π
3
Z
−
ω
t
)
∧
y
V
∕
m
from given equation signifies that the EM wave is moving in
Z
-axis,
(
⋀
z
)
General equation of electric field
E
=
E
0
sin
(
k
z
−
ω
t
)
we get,
k
=
2
π
3
∴
Wave vector
=
⋀
k
=
2
π
3
z
Wavelength of EM wave
∵
k
=
2
π
λ
=
2
π
3
⇒
λ
=
3
m
Frequency of EM wave
f
=
2
π
ω
H
z
Expression of magnetic field part
=
B
0
sin
(
k
z
−
ω
t
)
⋀
x
t
⇒
B
=
C
5
sin
(
2
π
3
Z
−
ω
t
)
⋀
x
t
(
∵
B
0
E
0
=
C
)
© examsnet.com
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