Given, rope length =1m and frequency =10 revolution\/second Here, rope length work as radius of this circular motion. ∴ Centripetal acceleration (ac)=
v2
r
∵v=ωr ⇒ac=
ω2r2
r
=ω2r Now putting the values ac=(2π10)2×1(∵ω=2πf) ⇒ac=3947≈4000m∕s2