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KVPY SX SB Exam 2015 Question Paper
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© examsnet.com
Question : 51
Total: 120
The electronic configuration of an element with the largest difference between the 1
st
and 2
nd
ionization energies is
1
s
2
2
s
2
2
p
6
1
s
2
2
s
2
2
p
6
3
s
1
1
s
2
2
s
2
2
p
6
3
s
2
1
s
2
2
s
2
2
p
1
Validate
Solution:
N
a
=
1
s
2
2
s
2
2
p
6
3
s
1
N
a
+
→
1
s
2
2
s
22
p
6
[
N
e
]
[Ne] is inert gas, so, electron removal is very difficult so I.P. is very high.
N
a
+
2
–
–
–
–
–
▸
1
s
2
2
s
2
2
p
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