Given: A number C is 2 times of the average of A, B and D The number B is equal to the average of A and D B = 16 Formula: Average of n numbers
a1,a2,...,an=(a1+a2+...+an)/n
Calculation: Given that C is 2 times of the average of A, B and D C=2(A+B+D)/3 ⇒3C=2A+2B+2D Number B is equal to the average of A and D B=(A+D)/2 ⇒2B=A+D Now, 3C=2A+2B+2D ⇒3C=2(A+D)+2B ⇒ 3C=2(2×16)+(2×16) ⇒3C=64+32 ⇒ 3C=96 ∴ C = 32