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Manipal Entrance Test 2013 Physics Paper
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© examsnet.com
Question : 47
Total: 60
A simple pendulum has time period
T
1
. The point of suspension is now moved upward according to the relation
y
=
k
t
2
(
k
=
1
m
s
2
)
where
y
is the vertical displacement. The time period now become
T
2
The ratio of
T
1
2
T
2
2
is
g
=
10
m
∕
s
2
6
5
5
6
1
4
5
Validate
Solution:
y
=
k
t
2
d
2
y
d
t
2
=
2
k
a
=
2
m
∕
s
2
T
1
=
2
π
√
l
g
T
2
=
2
π
√
l
g
+
a
y
T
1
2
T
2
2
=
g
+
a
y
g
=
10
+
2
10
=
6
5
© examsnet.com
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