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Manipal Entrance Test 2013 Physics Paper
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© examsnet.com
Question : 48
Total: 60
A electron is moving round the nucleus of ahydrogen atom in a circular orbit of radius r. The coulomb force F between the two is
k
e
2
r
3
r
−
k
e
2
r
3
r
k
e
2
r
2
r
−
k
e
2
r
2
r
Validate
Solution:
F
=
−
1
4
π
ε
0
q
1
q
2
r
2
=
r
F
=
−
k
q
1
q
2
r
2
=
r
F
=
−
k
e
.
e
r
2
^
r
=
−
k
e
2
r
2
^
r
^
r
=
r
|
r
|
=
r
r
F
=
−
k
e
2
r
2
.
r
r
=
−
k
e
2
r
3
r
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