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Manipal Entrance Test 2013 Physics Paper
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© examsnet.com
Question : 3
Total: 60
A ballon contains 1500 m
3
of a helium at 27°C and 4 atmospheric pressure. The volume of helium at -3 °C temperature and 2 atmo spheric pressure will be
2700 m
3
1700 m
3
1900 m
3
1500 m
3
Validate
Solution:
The general gas equation is
p
1
V
1
T
1
=
p
2
V
2
T
2
=
gas constant
where
p
1
,
V
1
,
p
2
,
V
2
are pressure and volume at temperatures
T
1
and
T
2
respectively.
Given
V
1
=
1500
m
3
,
T
1
=
27
+
273
=
300
K
P
1
=
4
atm
T
2
=
−
3
°
C
=
273
−
3
=
270
K
,
P
2
=
2
atm
∴
V
2
=
P
1
V
1
T
1
×
T
2
P
2
V
2
=
4
×
1500
300
×
270
2
V
2
=
2700
m
3
© examsnet.com
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