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Manipal Entrance Test 2015 Physics Paper
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© examsnet.com
Question : 11
Total: 50
Two coils have mutual inductance
0.005
H
The current changes in the first coil according to equation
I
=
I
0
sin
ω
t
,
where
I
0
=
10
A
and
ω
=
100
π
rad
∕
s
.
The maximum value of emf in the secondcoil is
12 π
8 π
5 π
2 π
Validate
Solution:
The instantaneous current in the
AC
circuit is given by
I
=
I
0
sin
ω
t
d
I
d
t
=
d
d
t
(
I
0
sin
ω
t
)
=
(
I
0
sin
ω
t
)
ω
Substituting
I
0
=
10
A
,
ω
=
100
π
cos
(
100
π
)
=
1
, we get
d
I
d
t
=
100
π
Hence, induced emf is given by
E
=
M
D
I
d
t
On putting
M
=
0.005
H
,
d
I
d
t
=
1000
π
,
we get
E
=
(
5
π
)
V
© examsnet.com
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