Time taken by the small ball to return to the hands of the juggler is
==4s. So, he is throwing the balls after 1 s each. Let at some instant, he throws the ball number
4. Before 1 s of throwing it, he throws ball 3. So, the height of ball 3 is
h=ut−gt2 h3=20×1−(10)(1)2=15m Before 2 s, he throws ball 2. So, the height of ball 2 is
h2=20×2−×10(2)2=20m Before 3 s, he throws ball 1. So, the height of ball 1 is
h1=20×3−×10(3)2=15m