The general equations of alternating voltage and current in an AC circuit are as follows E=E0‌sin‌ω‌t ...(i) I=I0‌sin‌ω‌t ...(ii) Given that, E=100‌sin‌100‌π‌t ...(iii) I=5‌sin‌100‌π‌t ...(iv) Comparing Eqs. (ii) and and (iv), we get, Peak value of current, I0 = 5A Comparing Eqs. (i) and (iii), we get Peak value of voltage, E0 = 100 V Now, r.m.s. value of voltage is given by Erms=
E0
√2
=
100
√2
V Similarly, r.m.s. value of current is given by Irms=