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MHTCET 2016 Physics Solved Paper
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© examsnet.com
Question : 16
Total: 50
Wire having tension 225 N produces six beats per second when it is tuned with a fork. When tension changes to 256 N, it is tuned with the same fork, the number of beats remain unchanged. The frequency of the fork will be
186Hz
225Hz
256Hz
280Hz
Validate
Solution:
(a) The fundamental frequency of vibrating wire is given by
f
I
=
1
2
√
T
µ
Here, µ = mass of string per unit length.
T = tension in the wire
Let x be the frequency of tunning for k according to question
(x -f) = ± 6
∴
f
1
=
1
2
L
√
225
µ
and
f
2
=
1
2
L
√
256
µ
∴
f
1
f
2
=
15
16
⇒
f
2
=
16
15
×
f
1
⇒
f
2
=
16
15
(
6
+
x
)
Equating the two cases of
f
1
we have
(x+ 6) =
16
15
( x - 6)
∴ 15x + 90 = 16x - 96
∴ x = 186Hz
© examsnet.com
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