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MHTCET 2016 Physics Solved Paper
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© examsnet.com
Question : 17
Total: 50
Assuming the expression for the pressure exerted by the gas on the walls of the container, it can be shown that pressure is
[
1
3
]
r
d
kinetic energy per unit volume of a gas
[
2
3
]
r
d
kinetic energy per unit volume of a gas
[
3
4
]
r
d
kinetic energy per unit volume of a gas
[
3
2
]
× kinetic energy per unit volume of a gas
Validate
Solution:
(b) As per kinetic theory of gases, the pressure exerted by the gas on the walls of container (p) is given by
p
=
p
0
+
p
1
+
p
2
i.e.
p
=
p
0
+
1
3
8
v
2
+
3
g
h
For a container,
p
1
=
1
3
ρ
v
2
=
1
3
m
v
⋅
v
2
×
2
2
=
2
3
⋅
1
2
m
v
2
⋅
1
v
=
2
3
v
K
E
[
∵
K
E
=
1
2
m
v
2
]
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