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NDA Math Circle

Question : 12 of 26

Marks: +1, -0

Solution:

(A)

Given diameter of circle = 44 cm ⇒ radius = 22 cm

Length of chord = 22 cm

Let AB be the given chord

From figure, it is clear that ∆OAB is equilateral triangle

∴ length of arc AB (minor) =

\frac{1}{6}

(Perimeter of circle)

\frac{1}{6}

( πD)

\frac{1}{6} \times \frac{22}{7}

× 44

\frac{484}{21}

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