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NDA Math Circle
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© examsnet.com
Question : 13
Total: 26
The equation of a circle whose end points of a diameter are
(
x
1
,
y
1
)
and
(
x
2
,
y
2
)
is
[NDA II 2018]
(
x
−
x
1
)
(
x
−
x
2
)
+
(
y
−
y
1
)
(
y
−
y
2
)
=
x
2
+
y
2
(
x
−
x
1
)
2
+
(
y
−
y
1
)
2
=
x
2
y
2
x
2
+
y
2
+
2
x
1
x
2
+
2
y
1
y
2
=
0
(
x
−
x
1
)
(
x
−
x
2
)
+
(
y
−
y
1
)
(
y
−
y
2
)
=
0
Validate
Solution:
Equation of circle is
(
x
−
x
1
)
(
x
−
x
2
)
+
(
y
−
y
1
)
(
y
−
y
2
)
=
0
© examsnet.com
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