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Class 12 NEET Physics Current Electricity Questions Part 1
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© examsnet.com
Question : 10
Total: 100
A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf of
2.0
V and a negligible internal resistance. The potentiometer wire itself is
4
m long. When the resistance, R, connected acrose the given cell, has values of.
(i) infinity (ii)
9.5
Ω
The 'balancing lengths, on the potentiometer wire are found to be
3
m and
2.85
m, respectively.
The value of internal resistance of the cell is:
[NEET 2014]
0.25
Ω
0.95
Ω
0.5
Ω
0.75
Ω
Validate
Solution:
👈: Video Solution
r
=
(
l
1
l
2
−
1
)
R
=
(
3
285
−
1
)
9.5
Ω
=
0.15
2.85
×
9.5
Ω
=
0.5
Ω
© examsnet.com
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