The situation is as shown in the figure. For a balancedWheatstone'sbridge
P
Q
=
R
S
∴
10Ω
30Ω
=
30Ω
90Ω
or
1
3
=
1
3
It is a balanced Wheatstone's bridge. Hence no current flows in the galvanometer arm. Hence, resistance 50Ω becomes ineffective. ∴ The equivalent resistance of the circuit is Req=5Ω+