Total heat gained by ice is equal to the total heat lost by steam. For ice to completely convert into water, heat required is m1Lf=1×80=80cal For steam to completely convert into water, heat released is m2Lv=1×540=540cal Hence, first 80 calories will not be enough for the steam to condense completely. Now, to convert melted water to 100∘C from 0∘C, heat required is m1s(100−0)=1×1×100=100cal So, total energy required to heat ice to water 100∘C is 100+80=180cal. Hence, even this amount of energy is not enough for the steam to condense completely. Hence, the final temperature of the mixture will be 100∘C. Note- finally the mixture will consist of both steam and water at 100∘C.