Let P be the end point of Lotus Rectum and P=(acosθ,bsinθ)...... (1) Now to Calculate, eccentric angle θ at the end of LR i.e. at P(acosθ,bsinθ) We know that from above figure P=(ae,
b2
a
).......(2) We will compare coordinates acosθ=ae bsinθ=b2∕a cosθ=e sinθ=b∕aWe get |tanθ|=