Let the numbers be x and y. ∴ x + y = 216 = 27 × 8 Since HCF of these two numbers is 27, hence, common factor of these two numbers is 27. Therefore these numbers will be of the form of 27 × 1, 27 × 2, 27 × 3, ... etc. According to the condition of the problem sum of these numbers is 216. ∴ The numbers will be 27 × 3 = 81 and 27 × 5 = 135